由已知,有
a=log18(9)=log2(9)/log2(18)=2log2(3)/[1+2log2(3)]
b=log18(5)=log2(5)/log2(18)=log2(5)/[1+2log2(3)]
由此解得 log2(3)=a/[2(1-a)],log2(5)=b/(1-a),
所以,根据对数换底公式得
log36(5)=log2(5)/log2(36)=log2(5)/[2+2log2(3)]=b/(2+a).