m²x²+1=(3-2m)xm²x²-(3-2m)x+1=0该方程有两个不等实根,则判别式大于0Δ=[-(3-2m)]²-4m²=-12m+9＞0,得m＜3/4且m≠0设该方程的两实根为x1、x2,由韦达定理有x1+x2=(3-2m)/m²、x1x2=...