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求x^2/根号x^3-1的不定积分
人气:459 ℃ 时间:2020-05-09 04:14:42
解答
∫x^2/根号x^3-1dx
=1/3∫(x³-1)^(-1/2)dx³
=1/3∫(x³-1)^(-1/2)d(x³-1)
=1/3×1/(-1/2+1)(x³-1)^(-1/2+1)+c
=2/3·√(x³-1)+c
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