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求6/5(sinθ+cosθ)-sinθ*cosθ的最大值和最小值
0<θ<90°
人气:217 ℃ 时间:2020-07-03 21:05:10
解答
原式=6/5[sinθ+sin(π/2-θ)]- sin(2θ)/2=12/5[sin(π/4) cos(θ-π/4)]- sin(2θ)/2=6√2/5 cos(θ-π/4)-cos(2θ-π/2)/2=6√2/5 cos(θ-π/4)-{2 [cos(θ-π/4)]^2-1}/2=-[cos(θ-π/4)]^2+6√2/5 cos(θ-π/4)...
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