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lim (tanx-sinx)/x^2*sinx x趋于0求极限怎么解
人气:480 ℃ 时间:2020-05-31 17:25:19
解答
lim (tanx-sinx)/(x^2*sinx)
= limtanx (1-cosx)/(x^2*sinx) (等价无穷小代换)
= limx (x^2/2)/(x^2*x) = 1/2
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