①(x^2/x+2-4/x+2)÷x-2/x②x-1/x+2÷x^2-2x+1/x^2-4+1/x-1③(xy-x^2)÷x^2-_数学解答

①(x^2/x+2-4/x+2)÷x-2/x②x-1/x+2÷x^2-2x+1/x^2-4+1/x-1③(xy-x^2)÷x^2-2xy+y^2/xy*x-y/y^2*yx^-2计算

人气：123 ℃　时间：2020-06-02 15:40:55

解答

①(x^2/x+2-4/x+2)÷x-2/x
=(x-2)*x/(x-2)
=x
②x-1/x+2÷x^2-2x+1/x^2-4+1/x-1
=(x-2)/(x-1)+1/(x-1)
=(x-1)/(x-1)
=1
③没有括号把分子分母分开实在太难看明白了.