2a^2-b^2-[(3a^2-4b^2)-(1/2a-b)]_其他解答

2a^2-b^2-[(3a^2-4b^2)-(1/2a-b)]

人气：475 ℃　时间：2020-02-02 13:08:10

解答

2a^2-b^2-[(3a^2-4b^2)-(1/2a-b)]
=2a²-b²-(3a²-4b²-1/2a+b)
=2a²-b²-3a²+4b²+1/2a-b
=-a²+3b²+1/2a-b