画出方程y=( |1-x^2|)^1/2的图像y=( |1-x^2|)^1/2,可知y≥0,等式两边平方得y^2=|1-x^2|(y≥0),1）当1-x^2≥0时,即-1≤x≤1时,y^2=1-x^2即y^2+x^2=1(y≥0),图形为以原点为圆心,以1为半径的在x轴上方半圆.2）当1-x^21...