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数学
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如图,在△ABC中,AB=AC,∠BAC=40°,分别以AB,AC为边作两个等腰直角三角形ABD和
ACE,使∠BAD=∠CAE=90°.
(1)求∠DBC的度数;
(2)求证:BD=CE.
人气:183 ℃ 时间:2019-08-17 20:07:22
解答
(1)∵△ABD为等腰直角三角形,∴∠DBA=45°.又∵AB=AC,∠BAC=40°,∴∠ABC=70°.∴∠DBC=115°;(2)证明:∵△ABD和△ACE均为等腰直角三角形,∴∠BAD=∠CAE=90°,AB=AD,AC=AE.又∵AB=AC,∴AB=AD=AC=AE...
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