配方得:x2+8x+42=9+42,
(x+4)2=25,
开方得:x+4=±5,
解得:x1=1,x2=-9;
(2)整理得:3x2-22x+24=0,
这里a=3,b=-22,c=24,
∵b2-4ac=(-22)2-4×3×24=216,
∴x=
22±
| ||
| 2×3 |
11±3
| ||
| 3 |
x1=
11+3
| ||
| 3 |
11−3
| ||
| 3 |
(3)移项得:7x(5x+2)-6(5x+2)=0,
(5x+2)(7x-6)=0,
5x+2=0,7x-6=0,
解得:x1=-
| 2 |
| 5 |
| 6 |
| 7 |
22±
| ||
| 2×3 |
11±3
| ||
| 3 |
11+3
| ||
| 3 |
11−3
| ||
| 3 |
| 2 |
| 5 |
| 6 |
| 7 |