已知 x-3y=0 求(2x+y)/(x²-2xy+y²)*(x-y)
有分……
人气:142 ℃ 时间:2019-08-20 12:24:56
解答
x-3y=0
x=3y
(2x+y)/(x²-2xy+y²)*(x-y)
=(2x+y)/(x-y)
=(7y)/(2y)
=7/2
推荐
- 已知x-3y=0,求2x+y/x2-2xy+y2•(x-y)的值.
- 已知x-3y=0,求2x+y/x²-2xy ×(x-y)的值
- 解方程组x²-2xy+y²=1 2x²-5xy-3y²=0
- 已知实数x,y满足条件|2x+3y+1|+(x+3y+5)²=0,求式子(-2xy)²×(-y²)×6xy²的值
- 当(x+1)²+(y+1)²=0时,求3(2x²-xy-y²)-2(x²-2xy-3y²)的值
- 为什么集邮在世界各地都有爱好者,为什么集邮
- I watched her ___(dance) in the classroom when I passed yesterday.I can watch her _(dance)every day
- 在三角形ABC中,a,b,c是角A,B,C的对边,若a,b,c成等比数列,A=60°,则b*sinB/c等于?
猜你喜欢