(1)求[8(x-y)四次方+(y-x)³]÷[2(x-y)²]结果
(2)已知x-y=1,xy=2,求x³y-2x²y²+xy³的值
人气:409 ℃ 时间:2019-08-28 10:24:15
解答
[8(x-y)四次方+(y-x)³]÷[2(x-y)²]
=8(x-y)四次方÷[2(x-y)²]-(x-y)³] ÷2(x-y)²]
=4(x-y)²-(x-y)/2
x³y-2x²y²+xy³
=xy(x²-2xy+y²)
=xy(x-y)²
=2第一个错了- -但是我不知道怎么写没错,只不过没有去掉括号罢了
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