梯形ABCD中,AD//BC,对角线AC⊥BD,AC=5cm,BD=12cm,则梯形的中位线长等于?没有图!
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人气:419 ℃ 时间:2019-09-28 09:15:21
解答
过A做AE平行于BD,交CB延长线于E,
易知AEBD为平行四边行,
BE=AD,AE平行于BD,则
AE垂直与AC,
三角形AEC为直角三角形,利用勾股定律EC平方=12平方+5平方,得EC=13
中位线长为1/2(AD+BC)=1/2(BE+BC)=1/2*CE=13/2
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