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(x^2-1)^2(3x-2)+(2-3x)的简便计算
人气:357 ℃ 时间:2020-07-07 13:39:17
解答
(x^2-1)^2(3x-2)+(2-3x)
=(x^2-1)^2(3x-2)-(3x-2)
=((x^2-1)^2-1)(3x-2)
=(x^2-1-1)(x^2-1+1)(3x-2)
=(x^2-2)x^2(3x-2)
=(x+根号2)(x-根号2)x^2(3x-2)
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