a2−1 |
a2+4a+4 |
a+1 |
a+2 |
=
(a+1)(a−1) |
(a+2)2 |
a+2 |
a+1 |
=
a−1 |
a+2 |
(2)
x−1 |
x−2 |
1 |
2−x |
方程的两边同乘(x-2),得
x-1+x+2=-1,
解得x=-1.
检验:把x=-1代入(x-2)=-3≠0.
故原方程的解为:x=-1.
a2−1 |
a2+4a+4 |
a+1 |
a+2 |
x−1 |
x−2 |
1 |
2−x |
a2−1 |
a2+4a+4 |
a+1 |
a+2 |
(a+1)(a−1) |
(a+2)2 |
a+2 |
a+1 |
a−1 |
a+2 |
x−1 |
x−2 |
1 |
2−x |