[(x-4)/(x-2)-x-2]/(x²-2x+1)/(x-2)=[(x-4)-(x+2)(x-2)]/(x²-2x+1)=(x-4-x²+4)/(x-1)²=x(1-x)/(x-1)²=x/(1-x)当x=0时原式=0/(1-0)=0如果不懂,祝学习愉快!可否说明一下x≠？分母不为0那么x≠1,x≠2