>
数学
>
计算(2+1)(22+1)(24+1)(28+1)(216+1)(232+1)+1
计算(2+1)(22+1)(24+1)(28+1)(216+1)(232+1)+1
注:上式中第二个括号中的2是上标,后面括号中的:4、8、16、32都是上标
人气:217 ℃ 时间:2020-02-03 00:13:07
解答
把这个式子最左边乘以一个(2-1)不改变结果,然后用平方差公式就能做出来了,结果是2的64次方
推荐
(2-1)(2+1) (22+1)(24+1)…(216+1)+1的个位数字
3(22+1)(24+1)(28+1)…(232+1)+1的个位数是( ) A.4 B.5 C.6 D.8
(2+1)(22+1)( 24+1)( 28+1)( 216+1)( 232+1)( 264+1)+1
(2+1) (22+1) (24+1) (28+1) (216+1) (232+1)+1
1、(21+1)×(22+1)×(24+1)×(28+1)×(216+1)×(232+1)×(264+1)的值
Go ()along the road.The bus stop is at the end of it.
什么是二倍角、什么是log
设定义在[-2.2]上的偶函数f(x)在区间[0.2]上单调递减,若f(1-m)
猜你喜欢
不等式x^2+mx+m/2>0对任意实数x恒成立,则实数a的取值范围是?
THe invention of internet helped bring into popular usage___a wide range of new words
大小两圆的直径比是3:2,小圆周长比大圆周长的1/2还多4.71厘米,求大圆半径和小圆面积
Will it b______ you if I turn on the radio该怎么写呢
(5m十1)的平方减(5m十1)乘(5m-1)
一道高一三角函数恒等变换题
lend me it 还是lend it to me
lt is six thirty in the morning.Ron m_____ get up.He puts up his clothes,but can't f_____ his shoes.He put them under th
© 2025 79432.Com All Rights Reserved.
电脑版
|
手机版