
AB=a,CD=b,由△AOF∽△CEF得
OF |
FE |
AO |
ED |
f |
FE |
| ||
|
b |
a |
那么光屏到凸透镜的距离为FE+OF=
b |
a |
b |
a |
(2)当一束与主光轴平行的光束经凸透镜折射后,还没有汇聚在焦点上时,即在焦点的左侧时,如下图所示:

AB=a,CD=b,由△AOF∽△CEF得
AO |
CE |
OF |
EF |
| ||
|
f |
EF |
b |
a |
那么光屏到凸透镜的距离为OF-FE=f-
b |
a |
b |
a |
故选BD.
OF |
FE |
AO |
ED |
f |
FE |
| ||
|
b |
a |
b |
a |
b |
a |
AO |
CE |
OF |
EF |
| ||
|
f |
EF |
b |
a |
b |
a |
b |
a |