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因式分解x²-3xy+2y²-2x+3y+1
x四次方+4
人气:395 ℃ 时间:2020-01-31 17:13:19
解答
x²-3xy+2y²-2x+3y+1
=(x-y)(x-2y)-(2x-3y)+1
=(x-y-1)(x-2y-1)
x⁴+4
=(x²)²+2²+4x²-4x²
=(x²+2)²-(2x)²
=(x²+2x+2)(x²-2x+2)
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