∵a＝(√2-1)／(√2+1)=(√2-1)^2/(√2+1)(√2-1)=3-2√2,
b＝√2+1／√2-1=3+2√2,
a+b=6
ab=1
∴(a+b+ab)／(a²+b^2)
=(6+1)/[(a+b)^2-2ab]
=7/(36-2)
=7/34