CD垂直AB于D,E是AB上一点.EF垂直AB与f,角1=角2请问角AGD=角ACB
人气：340 ℃ 时间：2020-03-25 05:29:24
解答
分析：如图,根据平行线的判定可知EF∥CD,则易证∠2=∠3,结合已知条件可以判定内错角∠1=∠3,则DG∥BC,故同位角∠AGD=∠ACB．
证明：如图,∵CD⊥AB,EF⊥AB,
∴EF∥CD,
∴∠2=∠3．
∵∠1=∠2,
∴∠1=∠3,
∴DG∥BC,
∴∠AGD=∠ACB．
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