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当|x+5|+(y-2)方=0时,求(4x-2y方)-[5x-(x-y)方]-x的值
人气:117 ℃ 时间:2020-08-19 10:14:29
解答
x+5=0 x=-5
y-2=0 y=2
(4x-2y^2)-[5x-(x-y)^2]-x
=[4×(-5)-2×2^2]-[5×(-5)-(-5-2)^2]-(-5)
=(-20-8)-(-25-49)+5
=51
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