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2重积分|x|+|y|dxdy,|x|+|y
人气:451 ℃ 时间:2020-06-07 16:12:19
解答
∫D∫|x|+|y|dS=4∫[0,1]∫[0,4-x](x+y)dxdy
=4∫[0,1]dx∫[0,4-x]d(xy+y^2/2)
=4∫[0,1](4-x)x+(1/2)(4-x)^2 dx
=4∫[0,1](-3/2)x^2-4x+8 dx
=2x^3-8x^2+32x |[0,1]
=2-8+32=24
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