求微分方程的通解：y'=((1-y^2)^(1/2))/((1-x^2)^(1/2))_数学解答

求微分方程的通解：y'=((1-y^2)^(1/2))/((1-x^2)^(1/2))

人气：495 ℃　时间：2020-05-13 19:37:52

解答

dy/dx=((1-y^2)^(1/2))/((1-x^2)^(1/2))
dy/(1-y^2)^(1/2)=dx/(1-x^2)^(1/2)
arcsiny=arcsinx+C