f(x)=(x-1)(x-2)(x-3).(x-99)(x-100)求f(1)的导数_数学解答

f(x)=(x-1)(x-2)(x-3).(x-99)(x-100)求f(1)的导数

人气：286 ℃　时间：2020-02-02 20:57:35

解答

f′(x)=(x-1)′［(x-2)(x-3)(x-4)……(x-100)］+(x-1)［(x-2)(x-3)(x-4)……(x-100)］′ f(x=1)=1×［(-1)(-2)(-3)……(-99)］+(1-1)［(x-2)(x-3)(x-4)……(x-100)］′ =-99!