给你个例子:
>> syms a b c d (定义变量)
>> A=[a,b;c,d] (定义矩阵)
A =
[ a,b]
[ c,d]
>> inv(A) (求矩阵的逆)
ans = (结果)
[ d/(a*d - b*c),-b/(a*d - b*c)]
[ -c/(a*d - b*c),a/(a*d - b*c)]