设函数f(x)=sinxcosx-根号3cos(π+x)cosx(x∈R).求f(x)最小周期
人气:263 ℃ 时间:2019-08-19 13:44:57
解答
利用诱导公式和三角恒定公式来解
f(x)=1/2 * sin2x+√ 3cos^2
f(x)=1/2*sin2x+√ 3*(1+cos2x)/2
f(x)=1/2*sin2x+√ 3/2*cos2x+√ 3/2
f(x)=sin(2x+π/3)+√ 3/2
T=2π/2=π
所以最小正周期为π
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