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sinA=1/2,sinB=1/3,sin(A+B)sin(A-B)=?
人气:281 ℃ 时间:2020-04-14 15:27:55
解答
=(sinacosb+sinbcosa)(sinacosb-sinbcosa)
=sina^2cosb^2-sinb^2cosa^2
=(1/2)^2[1-(1/3)^2]-(1/3)^2[1-(1/2)^2]
=2/9-1/12
=5/36
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