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1/(1-x)^2求不定积分;x乘根号下(1+2x^2)求不定积分;x/根号下(1-x^2)求不定积分
人气:126 ℃ 时间:2020-05-12 21:28:55
解答
1、∫dx/(1-x)^2=∫d(x-1)/(x-1)^2=-1/(x-1)+C2、∫x√(1+2x^2)dx=1/4*∫√(1+2x^2)d(1+2x^2)=1/4*2/3*(1+2x^2)^(3/2)+C=1/6*(1+2x^2)^(3/2)+C3、∫xdx/√(1-x^2)=-1/2*∫d(1-x^2)/√(1-x^2)=-1/2*2*√(1-x^2)+C=-√...
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