设倾斜角为α,
当y=√3x时
k=√3,tanα=√3,
α=kπ+π,k∈Z;
当y=-√3x时
k=-√3,tanα=-√3,
α=kπ+2π/3,k∈Z;或α=kπ-π/3,
所以终边落在直线y=+-√3x上的角的集合为：
{α|α=kπ+π/3,或α=kπ-π/3,k∈Z}= {α|α=kπ±π/3,k∈Z}.