√(3-√5)-√(3+√5)=√[(6-2√5)/2]-√[(6+2√5)/2]=√[(√5-1)^2/2-√[(√5+1)^2/2]=(√5-1)√(1/2)-(√5+1)√(1/2)=[(√5-1)-(√5+1)]√(1/2)=(√5-1-√5-1)√(1/2)=-2*√(1/2)=-√(4*1/2)=-√2...