x^2 - 2x + y^2 + 6y + 10 = 0,求分式 (x-y)/(x+y)_数学解答

x^2 - 2x + y^2 + 6y + 10 = 0,求分式 (x-y)/(x+y)

人气：318 ℃　时间：2020-01-29 21:34:59

解答

X＾2+Y＾2-2X-6Y+10=0
(X-1)^2+(Y-3)^2=0
X-1=0;Y-3=0
X=1,Y=3
(x-y)/(x+y)
=-1/2