若x,y,z满足3x+7y+z=1,4X+10y+z=2008,求分式(2007x+2007y+2007z)/(x+3y)的值1/_数学解答

若x,y,z满足3x+7y+z=1,4X+10y+z=2008,求分式(2007x+2007y+2007z)/(x+3y)的值
1/(x^2-2x+4)* (x^2-4/x+8) + 1/(x+8)

人气：151 ℃　时间：2020-04-13 23:10:25

解答

3x+7y+z=1.1
4X+10y+z=2008.2
2-1:x+3y=2007
所以(2007x+2007y+2007z)/(x+3y)=x+y+z
4X+10y+z=2008中x+3y=2007
所以x+y+z+3(x+3y)=2008
x+y+z=2008-3*2007=-4013
(2007x+2007y+2007z)/(x+3y)=-4013