观察下列算式:3^1=3,3^2=9,3^3=27,3^4=81,3^5=243,3^6=729,3^7=2187,3^8=6565,……
(1)通过观察,你发现3^n(n≥1且n为整数)的末位数的规律是_________________________
(2)用你所发现的规律求(3-1)(3+1)(3^2+1)(3^4+1)……(3^32+1)+1的个位数是多少?
人气:159 ℃ 时间:2019-08-18 15:56:31
解答
3,9,7,1循环
1,因为前面的个位数很快就会一直为0.
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