设直线与双曲线两个交点为A(x1,y1),B(x2,y2)将直线代入双曲线得3x^2-2x-5=0由韦达定理得x1+x2=2/3,...x1x2=-5/3由直线上两点距离公式得AB=[√(1+k^2)]*|x1-x2|所以|AB|^2=(1+k^2)*[(x1+x2)^2-4x1x2]=2*[4/9+20/3]=12...