该LED灯的电功率:
P=ULEDI=1.4V×0.02A=0.028W;
(2)电阻R两端的电压:
UR=U-ULED=5V-1.4V=3.6V,
通过R的电流:
IR=ILED=0.02A,
定值电阻R阻值:
R=
| UR |
| IR |
| 3.6V |
| 0.02A |
(3)设获得的光能为E,则:
LED灯消耗的电能:
WLED=
| E |
| 90% |
白炽灯消耗的电能:
W白炽灯=
| E |
| 20% |
则
| W白炽灯 |
| WLED |
| ||
|
即要获得同样多的光能,白炽灯需消耗的电能是LED灯的4.5倍.
故答案为:0.028;180;4.5.
