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化简并求值:1/2*a-[4b-c-(1/2*a-c)]+[6a-(b-c)],其中a=0.1,b=0.2,c=0.3
人气:313 ℃ 时间:2020-06-19 00:42:30
解答
a/2-[4b-c-(1/2*a-c)]+[6a-(b-c)]
=a/2-[4b-c-(a/2-c)]+[6a-b+c]
=a/2-[4b-c-a/2+c]+[6a-b+c]
=a/2-[4b-a/2]+[6a-b+c]
=a/2-4b+a/2+6a-b+c
=a-4b+6a-b+c
=7a-5b+c
=7*0.1-5*0.2+0.3
=0.7-1+0.3
=0
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