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求椭圆曲线(x平方/2)+(y平方/4)=1上点(1,√2)处的切线方程和法线方程
人气:212 ℃ 时间:2020-04-10 10:33:00
解答
2x^2 + y^2 = 44x + 2ydy/dx = 0dy = -2x/y(1,√2)切线的斜率-2/√2 = -√2,法线斜率=1/√2切线方程y-sqrt(2) = -sqrt(2)(x-1),sqrt(2)x + y = 2sqrt(2)法线y-sqrt(2) = (x-1)/sqrt(2)x - sqrt(2)y + 1 = 0...
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