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化简cos(α -π )tan(α-2π)tan(2π-α)/sin(π+α)
人气:207 ℃ 时间:2020-06-21 06:09:17
解答
cos(α -π )tan(α-2π)tan(2π-α)/sin(π+α)
=[-cos(α)]tan(α)[-tan(α)]/[-sin(α)]
=tan(α)[-tan(α)]/[tan(α)]
= -tan(α)
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