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已知x^2-3x+1=0,求2x^3-3x^2-7x+2009
人气:271 ℃ 时间:2020-02-06 00:38:07
解答
2x^3-3x^2-7x+2009
=2x(x^2-3x+1)+3x^2-9x+2009
=2x*0+3x^2-9x+2009
=3x^2-9x+2009
=3(x^2-3x+1)+2006
=3*0+2006
=2006
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