y=x及y=2x,y=1交点(1/2,1),(1,1)
则
∫∫e^y^2dσ
=∫[0,1]∫[y/2,y]e^y^2dxdy
=∫[0,1]e^y^2∫[y/2,y]dxdy
=∫[0,1]e^y^2*y/2dy
=1/4∫[0,1]e^y^2dy^2
=1/4e^y^2[0,1]
=1/4(e-1)