若三角形ABC的三边a、b、c满足a的平方加b的平方加c的平方加338等于10a加24b加26c,判断三角形的形状
人气:217 ℃ 时间:2019-08-18 14:25:05
解答
a²-10a+25+b²-24b+133+c²-26c+169=0(25+144+169=338)
(a-5)²+(b-12)²+(c-13)²=0
a=5,b=12,c=13
a²+b²=c²
所以是RT△
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