所以0
0
m<-1-√3,m>-1+√3
m>0
所以m>-1+√3
m²+2m-2<1
m²+2m-3<0
(m+3)(m-1)<0
-3
所以0
-1+√3
若a>1,则loga(x)是增函数
所以loga(-1+√3)
0
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