解:由题可得:[(a^2+3)/(a^2-1)]-[(a+1)/(a-1)]+1 =(a^2+3)/(a+1)(a-1) - (a+1)^2/(a+1)(a-1) +(a+1)(a-1)/(a+1)(a-1)=[a^2+3-(a^2+2a+1)+(a+1)(a-1)]/(a+1)(a-1)=(a^2+3-a^2-2a-1+a^2-1)/(a+1)(a-1)=(a^2-2a+1)/(a+1...