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4xy-{(x^2+5xy-y^2)-(x^2+3xy-2y^2)}其中x=-1/4y=-1/2
人气:119 ℃ 时间:2019-10-26 06:24:52
解答
因为x=-1/4,y=-1/2,所以:4xy-{(x²+5xy-y²)-(x²+3xy-2y²)}=4xy-(x²+5xy-y²-x²-3xy+2y²)=4xy-(2xy+y²)=2xy-y²=y(2x-y)=(-1/2)*[2*(-1/4)-(-1/2)]=(-1/2)*0=0
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