1/(x-5)+1/x=1/6
[x+(x-5)]/[x(x-5)]=1/6
(2x-5)/(x²-5x)=1/6
x²-5x=6(2x-5)
x²-5x=12x-30
x²-5x-12x+30=0
x²-17x+30=0
(x-2)(x-15)=0
x1=2,x2=15
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