1 2 -1 2 3 0 1 5 1 -2 0 3 -2 -4 1 6 求这个行列式的值
人气:475 ℃ 时间:2020-05-02 12:00:22
解答
r2-3r1,r3-r1,r4+2r1
1 2 -1 2
0 -6 4 -1
0 -4 1 1
0 0 -1 10
= 按第1列展开
-6 4 -1
-4 1 1
0 -1 10
c3+10c2
-6 4 39
-4 1 11
0 -1 0
= 按第2列展开
-6 39
-4 11
= -6*11+4*39
= 90
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