求证1/2(cos2a+cos2b)=cos(a+b)cos(a-b)
人气:284 ℃ 时间:2020-04-13 23:30:38
解答
1/2(cos2a+cos2b)=cos(a+b)cos(a-b)证明:右边=(cosacosb-sinasinb)(cosacosb+sinasinb)=(cosacosb)^2-(sinasinb)^2=cos^2a(1-sin^2b)-(1-cos^2a)sin^2b=cos^2a-cos^2asin^2b-sin^2b+cos^2asin^2b=cos^2a-sin^...
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