则
|
|
∵y′=f(x′)=
| 2x′ |
| x′+1 |
∴y=
| 2(4-x) |
| 4-x+1 |
| 8-2x |
| 5-x |
| 2x-8 |
| x-5 |
故g(x)=
| 2x-8 |
| x-5 |
(2)∵Φ(x+2)=
| 1 |
| Φ(x) |
∴Φ(x+4)=
| 1 |
| Φ(x+2) |
即Φ(x)是周期为4的周期函数,
则Φ(2005)=Φ(2004+1)=Φ(1)=Φ(-3)=
| 1 |
| Φ(-3+2) |
| 1 |
| Φ(-1) |
| 1 |
| g(-1) |
| 1 | ||
|
| 6 |
| 10 |
| 3 |
| 5 |
故Φ(2005)=
| 3 |
| 5 |
| 2x |
| x+1 |
| 1 |
| Φ(x) |
|
|
| 2x′ |
| x′+1 |
| 2(4-x) |
| 4-x+1 |
| 8-2x |
| 5-x |
| 2x-8 |
| x-5 |
| 2x-8 |
| x-5 |
| 1 |
| Φ(x) |
| 1 |
| Φ(x+2) |
| 1 |
| Φ(-3+2) |
| 1 |
| Φ(-1) |
| 1 |
| g(-1) |
| 1 | ||
|
| 6 |
| 10 |
| 3 |
| 5 |
| 3 |
| 5 |