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已知x/y=8,求x^2-3xy+2y^2/x^2-5xy+4y^2的值.
人气:195 ℃ 时间:2020-04-09 00:44:37
解答
由于x/y=8,x=8y且Y不等于0,
(x^2-3xy+2y^2)/(x^2-5xy+4y^2)
=(X-Y)(X-2Y)/(X-Y)(X-4Y)
=(X-2Y)/(X-4Y)
所以上式为
(8Y-2Y)/(8Y-4Y)=6/4=3/2=1.5
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